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Web dev master please help

trumpoikot

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Nov 16, 2021
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patulong po, eto po kasi yung code ko for duplicate checker for 2 inputs.
ngayon pag mag eedit na ako na reread nya pa din itong code ko which is duplicate entry. please patulong po.
code working fine for checking duplicate entry, pero pag i eedit kuna yung data at mag sasave pagkatapos i edit na dededect nya as duplicate entry.

var test_port= true;
var server = $("#server").val();
var port = $("#port").val();



$.ajax({
url: "check_availability_server.php",
method: "POST",
data: {
server: server,
port: port
},
async: false,
dataType: "text",
success: function(result) {
if(result == "1")
{
test_port= true;
console.log("test_port exist true")
}
else {
test_port= false;
console.log("test_port exist false")
}
}
});




if(test_port) {
$('#availability').html('<span id="test" class="text-danger"> not available</span>');
$('#availability_port').html('<span id="test2" class="text-danger"> not available</span>');



var spanid = document.querySelector("#test")
spanid.focus()

alert("Check port Server. Duplicate entry")

console.log("not available checker")
return false
}
else
{
$('#availability').html('<span id="test" class="text-success"> available</span>');
$('#availability_port').html('<span id="test2" class="text-success"> available</span>');

}




///// end of validation server & port
 

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