Help Pa help po calculus

[Rojen G Embate]

Pwede po makahingi solutions nito para makapag aralan ko po

 

[Slime-]

To differentiate Y with respect to x, we can use the power rule and the chain rule of differentiation.

Y = x + 1/√x

Y' = d/dx(x) + d/dx(1/√x)

Applying the power rule and chain rule:

Y' = 1 + (-1/2)x^(-3/2)

Simplifying the second term:

Y' = 1 - 1/(2x^(3/2))

Therefore, the derivative of Y with respect to x is:

Y' = 1 - 1/(2x^(3/2))

To differentiate Y with respect to x, we can use the power rule and the chain rule of differentiation.

Y = x⁴ + √x

Y' = d/dx(x⁴) + d/dx(√x)

Applying the power rule and chain rule:

Y' = 4x³ + (1/2)x^(-1/2)

Simplifying the second term:

Y' = 4x³ + 1/(2√x)

Therefore, the derivative of Y with respect to x is:

Y' = 4x³ + 1/(2√x)

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Can you get the 2nd and 3rd order differential of this: Y= x+1/√x

Sure, we can find the 2nd and 3rd order derivatives of Y with respect to x using the power rule and the chain rule of differentiation.

First, let's find the first derivative of Y:

Y = x + 1/√x

Y' = 1 - 1/(2x^(3/2))

Next, we can differentiate Y' to find the second derivative:

Y'' = d/dx(1 - 1/(2x^(3/2)))

Using the power rule and chain rule:

Y'' = 3/(4x^(5/2))

Therefore, the second derivative of Y with respect to x is:

Y'' = 3/(4x^(5/2))

To find the third derivative of Y, we differentiate Y'' with respect to x:

Y''' = d/dx(3/(4x^(5/2)))

Using the power rule and chain rule:

Y''' = -15/(8x^(7/2))

Therefore, the third derivative of Y with respect to x is:

Y''' = -15/(8x^(7/2))

 

[Rojen G Embate]

To differentiate Y with respect to x, we can use the power rule and the chain rule of differentiation.

Y = x + 1/√x

Y' = d/dx(x) + d/dx(1/√x)

Applying the power rule and chain rule:

Y' = 1 + (-1/2)x^(-3/2)

Simplifying the second term:

Y' = 1 - 1/(2x^(3/2))

Therefore, the derivative of Y with respect to x is:

Y' = 1 - 1/(2x^(3/2))

To differentiate Y with respect to x, we can use the power rule and the chain rule of differentiation.

Y = x⁴ + √x

Y' = d/dx(x⁴) + d/dx(√x)

Applying the power rule and chain rule:

Y' = 4x³ + (1/2)x^(-1/2)

Simplifying the second term:

Y' = 4x³ + 1/(2√x)

Therefore, the derivative of Y with respect to x is:

Y' = 4x³ + 1/(2√x)

------
Can you get the 2nd and 3rd order differential of this: Y= x+1/√x

Sure, we can find the 2nd and 3rd order derivatives of Y with respect to x using the power rule and the chain rule of differentiation.

First, let's find the first derivative of Y:

Y = x + 1/√x

Y' = 1 - 1/(2x^(3/2))

Next, we can differentiate Y' to find the second derivative:

Y'' = d/dx(1 - 1/(2x^(3/2)))

Using the power rule and chain rule:

Y'' = 3/(4x^(5/2))

Therefore, the second derivative of Y with respect to x is:

Y'' = 3/(4x^(5/2))

To find the third derivative of Y, we differentiate Y'' with respect to x:

Y''' = d/dx(3/(4x^(5/2)))

Using the power rule and chain rule:

Y''' = -15/(8x^(7/2))

Therefore, the third derivative of Y with respect to x is:

Y''' = -15/(8x^(7/2))

wala po bang pina easy method jan yong walang mga ganto po ^, /, )) di ko po ma gets

 

[Slime-]

wala po bang pina easy method jan yong walang mga ganto po ^, /, )) di ko po ma gets

Bigay lang din ni chatgpt yan hahaha

Ito may explanation nya

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[Rojen G Embate]

Bigay lang din ni chatgpt yan hahaha

Ito may explanation nya

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lods pano naman sa number 3 at 4