Q: A water cooler uses 50kg/hr of melting ice to cool running water from 28°C to 8°C. Based on the outside coil area, Uo = 630 W/m²-K. If Cp of water is 4.186 kj/kg-K and heat of fusion of ice is 334 kj/kg, find a) LMTD b)Area of outside coil.
Tanong ko lang po if yung sa LMTD, constant na 0°C yung sa temperature ng ice or gagamitin po is mCp(∆T) = Q? Need pa po ba siyang iconvert sa Kelvin?
Tanong ko lang po if yung sa LMTD, constant na 0°C yung sa temperature ng ice or gagamitin po is mCp(∆T) = Q? Need pa po ba siyang iconvert sa Kelvin?