How to compute Sample Size? (thesis)

[_Big Boss_]

Pa compute naman po nito at patingin po ng solution. Kahiya-hiya man po. Thank you po

 

[42697262]

What have you done so far? I don't like spoonfeeding people when they have not provided their own solution when a simple search on the internet is enough.

Also, since hindi given your instructions, di ko alam yung tamang procedure.

 

[_Big Boss_]

What have you done so far? I don't like spoonfeeding people when they have not provided their own solution when a simple search on the internet is enough.

Also, since hindi given your instructions, di ko alam yung tamang procedure.

Sample size
POLICE : 48 = 88%
Residents : 383 = 0.43%

Eto po yung computation ko pero not sure po.

 

[42697262]

Sample size
POLICE : 48 = 88%
Residents : 383 = 0.43%

Eto po yung computation ko pero not sure po.

Ganyan din na kuha ko:

def szu(z, e, P):
    return ((z**2)*P*(1-P))/e**2

def sz(N, z, e, P):
    return szu(z, e, P)/ (1 + szu(z, e, P)/N)

print(sz(54, 1.96, 0.05, 0.5))
print(sz(87693, 1.96, 0.05, 0.5))

47 with 88.89%
382 with 0.44%

 

[_Big Boss_]

Ganyan din na kuha ko:

View attachment 2145404

def szu(z, e, P):
    return ((z**2)*P*(1-P))/e**2

def sz(N, z, e, P):
    return szu(z, e, P)/ (1 + szu(z, e, P)/N)

print(sz(54, 1.96, 0.05, 0.5))
print(sz(87693, 1.96, 0.05, 0.5))

47 with 88.89%
382 with 0.44%

Ah maigi po at same tayo ng compute. Baka tama nga po. Thank you po.

 

[42697262]

Ah maigi po at same tayo ng compute. Baka tama nga po. Thank you po.

naka depende lang yan sa gamit mong confidence level at standard deviation so do whatever you want. try lang din cross reference sa ibang tao