F Ferocity Honorary Poster Joined Nov 8, 2016 Posts 123 Reaction 14 Points 172 Age 24 Jun 9, 2019 #1 Pa help dito mga sir, iproprove daw using rational functions of sinx and cosx, or weierstrass. Attachments You do not have permission to view the full content of this post. Log in or register now.
R Roby Robyn Eternal Poster Established Jun 9, 2019 #3 Rewrite mo to tapos check ko csc udu= csc u (csc u+cot u / csc u+cot u) du Let u=csc u + cot u So du= (-csc u cot u - csc^2 u)du = csc u + cot u csc udu= - du / u Integral nito -ln |u| + c Tapos balik mo lang -ln |csc u + cot u| + C Attachments You do not have permission to view the full content of this post. Log in or register now.
Rewrite mo to tapos check ko csc udu= csc u (csc u+cot u / csc u+cot u) du Let u=csc u + cot u So du= (-csc u cot u - csc^2 u)du = csc u + cot u csc udu= - du / u Integral nito -ln |u| + c Tapos balik mo lang -ln |csc u + cot u| + C
P PHC-BlackNight Eternal Poster Jun 9, 2019 #4 RobyRobyn00 said: Rewrite mo to tapos check ko csc udu= csc u (csc u+cot u / csc u+cot u) du Let u=csc u + cot u So du= (-csc u cot u - csc^2 u)du = csc u + cot u csc udu= - du / u Integral nito -ln |u| + c Tapos balik mo lang -ln |csc u + cot u| + C Click to expand... Talino ni paps Attachments You do not have permission to view the full content of this post. Log in or register now.
RobyRobyn00 said: Rewrite mo to tapos check ko csc udu= csc u (csc u+cot u / csc u+cot u) du Let u=csc u + cot u So du= (-csc u cot u - csc^2 u)du = csc u + cot u csc udu= - du / u Integral nito -ln |u| + c Tapos balik mo lang -ln |csc u + cot u| + C Click to expand... Talino ni paps
R Roby Robyn Eternal Poster Established Jun 9, 2019 #5 Eto rin cot udu= (cos u / sin u ) du Let u=sin u So du= cos u du Sub mo na lang yung du=cos u, tapos u =sin u (cos u / sin u) du= u / du Integral nito =ln |u| + C Balik mo lang cot udu= ln |sin u| + C Attachments You do not have permission to view the full content of this post. Log in or register now.
Eto rin cot udu= (cos u / sin u ) du Let u=sin u So du= cos u du Sub mo na lang yung du=cos u, tapos u =sin u (cos u / sin u) du= u / du Integral nito =ln |u| + C Balik mo lang cot udu= ln |sin u| + C
R Roby Robyn Eternal Poster Established Jun 9, 2019 #6 BlackNight3226 said: Talino ni paps Click to expand... Haha di naman napag aralan lang