Closed C++ triangle without array

[alchemist_19]

#include <iostream>
using namespace std;
int main(int argc, char** argv) {
int row, a, b, spa=1;
cout<<"Rows: ";
cin>>row;
spa=row-1;
for(b=1;b<=row;b++)
{
for(a=1;a<=spa;a++)
{
cout<<" ";
}
spa--;
for(a=1;a<=2*b-1;a++)
cout<<"*";
cout<<"\n";
}
}
return 0;}

output:
Rows: 3
*
***
******

Paano gawin ito ng walang looping?
wag lang yung
cout<<"*"
cout<<"***"
cout<<"****"

Salamat mga master.

 

[Jmrie_]

navikenty

 

[PadrePatatas]

alchemist_19
Mali nman title mo at sana inaayos mo nman yung format ng code mo. Ang hirap basahin eh.

Dun naman sa tanong mo na walang looping. Hindi yan pwede ng walang looping.
1) Kung fixed yung row count. Pwedeng isa lang yung 'cout' pero sama-sama na dun yung string.

const int row = 3;

std::cout << "  *\n ***\n*****"

2) Pwede kang gumamit ng 'goto' pero looping din ito, iba lang itsura.

#include <iostream>
using namespace std;

int main(int argc, char** argv)
{
    int row, a, b, spa = 1;
    cout << "Rows: ";
    cin >> row;
    spa = row - 1;
    
    //for (b = 1; b <= row; b++) {
    b = 1;
begin_loop_1:
    if (b <= row) {
        //for (a = 1; a <= spa; a++) {
        a = 1;
begin_loop_2:
        if (a <= spa) {
            cout << " ";
            ++a;
            
             goto begin_loop_2;
        }
        
        spa--;
        //for (a = 1; a <= 2 * b - 1; a++)
        a = 1;
begin_loop_3:
        if (a <= 2 * b - 1) {
            cout << "*";
            ++a;
            
            goto begin_loop_3;
        }
        cout << "\n";
        ++b;
        
        goto begin_loop_1;
    }

    return 0;
}

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