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Closed Patulong po about java looping

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GDragon07

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Enter a number n and display the first n even numbers

Sample:
Enter n: 5
The first 5 even numbers are 2, 4, 6, 8, 10.
 
gulo ng tanong mo ts. bago ka magagawa ng program dapat naiintindihan mo muna yung gustong ipagawa sa program
 
C++:
#include <iostream>
using namespace std;
 
int main()
{
    int inputedNum = 0;
    
    cout<<"Input Number :"<<endl;
    cin>>inputedNum;
    
    for (int n = inputedNum ; n > 0; n--)
    {
        if (n%2 == 0)
        {
            cout<<n<<endl;
        }
    }
}
 
Ang gusto yata ni TS ay yung count ng even numbers. At hindi yung even numbers within a range.

C++:
#include <iostream>

int main(void) {
    int input {0};
    int myindex {0};
    std::cout << "Enter number of even numbers to display: " << std::flush;
    std::cin >> input;
    int *array_even_num = new int[input] {};
    for (int i=2; array_even_num[input-1] == 0; i++) {
        if (i%2 == 0) {
            array_even_num[myindex++] = i;
        }
    }

    std::cout << std::endl;
    for (int i=0; i<input; i++) {
        std::cout << "Element" << "[" << i << "] -- "  << array_even_num[i] << std::endl;
    }
    delete[] array_even_num;
    return 0;
}
 

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nakalimutan ko na mg java...display "n" numbers of even numbers sabi ni ts.

n=1: 2
n=2: 2 4
n=3: 2 4 6
n=4: 2 4 6 8
 
pa try nito paps
Java:
import java.util.Scanner;
public class PrintingEvenNumbers {
static Scanner in = new Scanner(System.in);
    public static void main(String[] args) {
        int number;
        System.out.print("Enter how many even Integer: ");
        number = in.nextInt();
        for(int i = 1 ; number > 0 ; i++) {
            if((i % 2) == 0) {
                System.out.print(i + " ");
            number--;
            }
        }
    }
}
 
Maraming salamat po sa inyo. At first madali lang akong nakaintindi sa if else pero sa looping medyo mahina ako hahaha
 
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