Closed Mailbox, open and close, array c++

[alchemist_19]

Ano yung code para dito?
Nag start siya sa 2, and then 3...
Kapag binalikan nya yung box na 0(close) ay gagawin nyang 1(open). Vice versa.
Pa request po hanggang Box 150.
Sa 150 na yun po DAW ay may 12 na closed at 138 open boxes.
Gamit lang ang array, loopings, conditional statement.

Ang output ya po ay yung huli(150) at kung ilan ang 0(close) at 1(open)
Salamat mga master. Beginner here:

000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000.

12 are close.
138 are open.

Ps. Diko alam saan banda yung 1(open)

 

[FreeAllYouCan-OFFICIAL]

madali lang yan

nested for loop

outside loop is row

inside loop is column

check every iteration bawat location then gawan ng if else statement or kahit if statement lang

 

[alchemist_19]

madali lang yan

nested for loop

outside loop is row

inside loop is column

check every iteration bawat location then gawan ng if else statement or kahit if statement lang

Pwede patingin yun code mo? salamat

 

[FreeAllYouCan-OFFICIAL]

Pwede patingin yun code mo? salamat

paano ka matututo niyan?

 

[alchemist_19]

paano ka matututo niyan?

Haha sabagay.

 

[alchemist_19]

Haha sabagay.

int mailbox[151], i;

for(i=1;i<151;i++)
{
for(j=1;j<151;j++)
{
if()

}
}

 

[aa1012]

pano sasagutin yung gantong tanong e ang gulo.