Closed Ang gulo! haha

[xxxolayxxx]

Sample Run:
Enter a number: 12534 <----- int num
5 is the hight digits in 12534
-
eh? yung ginawa po nung prof namin sa exam. (int num) lang.. hindi naman naka array. what i mean isang input lang pero nakuha nya yung 5 as highest? Paano po yun mga paps? help pp hehe salamat

 

[SpectaculairE]

google po:

You do not have permission to view the full content of this post. Log in or register now.

 

[xxxolayxxx]

Wala naman sa google paps.
This is the example.
int num = 12534;
Tass ang output nya,
5 is the highest digit in 12534.
-
ang logic... hindi naman array yung initialize at fix value sya. then paano na call ng ganun na lang. Hehe

 

[SpectaculairE]

binuksan mo yung link?

You do not have permission to view the full content of this post. Log in or register now.
public static void main(String[] args) {
int smallest = 0;
int large = 0;
int num;
System.out.println("enter the number");//how many number you want to enter
Scanner input = new Scanner(System.in);
int n = input.nextInt();
num = input.nextInt();
smallest = num; //assume first entered number as small one
// i starts from 2 because we already took one num value
for (int i = 2; i < n; i++) {
num = input.nextInt();
//comparing each time entered number with large one
if (num > large) {
large = num;
}
//comparing each time entered number with smallest one
if (num < smallest) {
smallest = num;
}
}
System.out.println("the largest is:" + large);
System.out.println("Smallest no is : " + smallest);
}


check mo to, ang ginagawa ay icompore yung una sa pangalawa and so on tapos kung ano yung pinka malaki ay naka store

 

[RollerCoaster]

I believe this is the solution of your Professor. He used division and modulo operator. Division by 10 in an integer and assign it within itself will remove its last digit + doing modulo operator by 10 will get the last digit.

import java.util.Scanner;

public class Main{
  public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    int num, temp, max = 0;
    num = in.nextInt();

    while(num > 0){
      temp = num % 10;
      num  = num / 10;
      if(temp > max){
        max = temp;
      }
      // System.out.println("get=" + temp + ":" + "remain=" + num);
    }
    System.out.println(max);
  }
}

Note: remove the comment part if you want to trace extraction

 

[angelofmercy]

Pinagawa sa amin yan sir. Ang
ginawa ko,

yong int, convert ko muna sa string.

String temp = String.valueOf(num);

Tapos, inisa isa kong nilagay sa arraylist

ArrayList <Integer> tempLi = new ArrayList <> ();
for(int x = 0; x != temp.length(); x++){
tempLi.add(Integer.valueOf(temp.charAt(x) +""));
}
Collections.sort(tempLi);
System.out.print("highest : " +tempLi.get(tempLi.size() -1));