Closed Labas na mga matalino sa math

[Oh No_]

Beyond the Essence

It is known that an equation of the graph obtained by rotating the graph of a certain equation about the origin clockwise by 45° (one-eighth of a complete clockwise turn) is obtained by simply replacing x and y in the original equation by ÷2/2(x-y), respectively using this algebraic method, identify the graph of xy=1.

Pasagot narin TIA

 

[FreeAllYouCan-OFFICIAL]

graph of xy=1 is "wala na finish na"

 

[SPNL Sinz]

graph of xy=1 is "wala na finish na"

Wala na bagsak na

 

[winrichdumlao08]

medyo magulo po itong part na ito ÷2/2(x-y), pwede makita yung mismong tanong? I mean if you have the original equation that we can work with? picture ng equation?

 

[Oh No_]

medyo magulo po itong part na ito ÷2/2(x-y), pwede makita yung mismong tanong? I mean if you have the original equation that we can work with? picture ng equation?

Salamat po

 

[Oh No_]

medyo magulo po itong part na ito ÷2/2(x-y), pwede makita yung mismong tanong? I mean if you have the original equation that we can work with? picture ng equation?

Salamat po

 

[PHC-SLXKYS]

Center=(1,1)
R= 1

Tama ba? Bubu aq ihh.. Hahaha palaging absent

 

[Smoke_Weed]

Nasa origin ata center nyan?

 

[faye422]

Hyperbola ung xy=1 sir.
Center = (0,0)
Opens quadrant 1 & 3. Asymptote nia is x&y axis.

 

[faye422]

Ung xy=1, replace mo x=√2/2 (x-y) , y=√2/2 (x+y)

Final equation x^2/2 - y^2/2 = 1