Closed Basic math problem

[Oh No_]

Pasagot naman po sadyang mahina lang po talaga ako sa Math

Pacomplete formula narin.
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Graph at distance formula po.
(-6+5),(-8-7)
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Determine eccentricity of the conic with equation.
25x²+y²-100x+6y+84=0
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yun lang po mga ka pH maraming salamat narin sa tutulong.

 

[5413363]

Vertices po ba yang ordered pair na yan?

 

[maxitor527]

kung graph po yan bilog po kakalabasan

 

[faye422]

Pakielaborate po ung (-6+5),(-8-7)

Coordinates po b yan?

 

[mrHazan]

Kulang sa instruction. What to solve?

 

[maxitor527]

ayan po itsura nya pag nagraph

 

[edlazile]

ilipat nio po muna sa standard form: (x-h)^2/a^2 + (y-k)^2/b^2 =1 para makuha ninyo ung value ng a and b. then use the formula in finding the eccentricity ng ellipse. e = sq. rt. (1 - b^2/a^2)

 

[edlazile]

yung isa naman po ay distance formula ang gagamitin ninyo, d=sq. rt. (difference in x)^2 + (difference in y)^2
goodluck po,

 

[edlazile]

ayan po itsura nya pag nagraph

ganito rin po graph ko, nasa (2,-3) ang center ng ellipse.

 

[Oh No_]

ilipat nio po muna sa standard form: (x-h)^2/a^2 + (y-k)^2/b^2 =1 para makuha ninyo ung value ng a and b. then use the formula in finding the eccentricity ng ellipse. e = sq. rt. (1 - b^2/a^2)

Pasample naman po

 

[Oh No_]

yung isa naman po ay distance formula ang gagamitin ninyo, d=sq. rt. (difference in x)^2 + (difference in y)^2
goodluck po,

Pasagot nalang po nito please
25x²+y²-100x+6y+84=0

 

[faye422]

Pasagot nalang po nito please
25x²+y²-100x+6y+84=0

(X+2)^2 + (Y-3)^2 / 5^2 = 1
h=-2
k=3
a=1
b=5
e=2√6 / 5

Correct me if i'm wrong. Hehe
Sana makatulong sir.

 

[faye422]

(X+2)^2 + (Y-3)^2 / 5^2 = 1
h=-2
k=3
a=1
b=5
e=2√6 / 5

Correct me if i'm wrong. Hehe
Sana makatulong sir.

a>b always yan kaya a=5 , b=1

 

[crinoldubat]

Just trying